Production Calculation of Circular Knitting Machine:
Production calculation is an important task for the textile engineers who is responsible for the knitting floor. There are so many who wants to make his career in textile knitting industry. He should have clear idea about knit fabric production. As its importance, this article has presented an easy method for calculating knit fabric production in textile knitting sector.
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| Circular knitting machine |
Circular Knitting Production Calculation Method in Textile:
To calculate production capacity of circular knitting machine in textile industry, the below formula has to follow:
Production in weight (kg) per hour,
∏×D×G× RPM of cylinder × Number of feeder × loop length in mm × tex×60× efficiency
=…………………………………………………………………..……….……………..………………
1000×1000×1000
Where,
D= Cylinder dia in inch,
G= Machine gauge in inch,
Now, I will present here some examples of knit fabric production calculation which will help you to understand the above formula.
Example-01:
Calculate the production of a single jersey circular knitting machine in kg per shift from the below data:
Machine gauge= 18,
Machine cylinder diameter= 30 inch,
Machine cylinder RPM= 38,
Loop length= 2 mm,
Number of feeder= 80,
Yarn count= 70 tex,
Efficiency= 95%,
Time (shift) = 8 hours.
Solution:
Here,
Time (shift) = (60×8) hour = 480 hour,
Efficiency= 95%=0.95,
Production in kg per hour=?
So,
Production in weight (kg) per hour,
∏×D×G× RPM of cylinder × Number of feeder × loop length in mm × tex×60× efficiency
=…………………………………………………………………..…………………………………………………………………….……
1000×1000×1000
3.14×30×18×38×80×2×70×480×0.95
=………………………………………………….
1000×1000×1000
= 329.07 kg per shift
So, production of single jersey circular knitting machine per shift is 329.07kg.
Example-02:
Following the below data, calculate the knit fabric production calculation per day of a circular knitting machine.
Machine diameter= 30 inch,
Machine gauge in inch= 20,
Number of feeder= 85,
Yarn count= 28 Ne,
Cylinder RPM= 30,
Loop length or stitch length= 2 mm,
Time= 1 day.
Solution:
Here,
Machine efficiency= 85%=0.85,
Time= 1 day= (24×60) hour= 1440 hours
So,
Production in kg per day,
∏×D×G× RPM of cylinder × Number of feeder × loop length in mm × tex×60× efficiency
=…………………………………………………………………..…………………………………………………………………………..…… (1)
1000×1000×1000
Now,
Ne × Tex= 590.5
Or, Tex= (590.5/Ne) = (590.5/28) = 21.09
Now, from equation (1), we get,
Production in kg per day,
3.14×30×20×30×85×2×21.09×1440×0.85
=………………………………………………………….
1000×1000×1000
= 248.03 kg
So, fabric production of circular knitting machine is 248.03kg
