# Important Formula for Knitting Production Calculation with Examples

How to Calculate Knitting Production in Textile?
To calculate the knitting production in textile, you have to know some formula. In another article I have shared the production calculation of circular knitting machine. This article has presented some important formulas of knitting calculation with examples. Hope it will be very useful in your job profession.
 Circular knitting machine
Knitting Calculation Formula:
Some important formula of knitting production calculation have mentioned in the below:

1. Production in length,
= Course per minute/ Course per inch,

Or,
= CPM/CPI

Or,
Number of feeder× cylinder RPM× time× efficiency
=…………………………………………………………………..
CPI×36

2. Course per inch,
= Course per minute/production in length

3. Course per minute,
= course per inch× production in length

4. Stitch density,
= Course per cm/ Wales per cm

5. Fabric width,
= {(∏× diameter of cylinder× machine gauge)/wales per cm}

Or,
= Number of wales/Wales per cm

Or,
= Number of needle/ wales per cm

6. Fabric weight,
= {(Course per minute× yarn length per course)/ yarn count}

7. Needle number of machine,
= ∏× diameter of cylinder× gauge

8. Yarn length per course,
= Total number of machine× loop length

9. Production of single jersey machine in weight (kg) per hour,
∏×cylinder dia (inch)×cylinder RPM× feeder no.× gauge×stitch length (mm)× tex×60×efficiency
=……………………………………………………………………………………………..……………
1000×1000×1000

10. Production of double jersey in length,
= Single jersey production in length/2

11. Production of double jersey in weight,
= Single jersey ×2

Production Calculation of Knitting Machine in Textile:

Example-01:
If machine diameter= 20 inch, feeder number= 90, course per cm= 15, machine speed= 25 RPM and machine efficiency is 90% then calculate the production per shift of a single jersey circular knitting machine.

Solution:
Here,
Diameter of machine= 20 inch,
Number of feeder= 90,
Machine speed or machine cylinder RPM= 25 RPM,
Machine efficiency= 90%= 0.9,
Time= 1 shift= 8 hours = (8×60) =480 minute
Course per cm= 15,
Course per inch (CPI) = (15/0.3937) = 38.10≈38

So,
Production in meter per shift,
No. of feeder× cylinder RPM× time× efficiency
=…………………………………………………………..

CPI×36

90×25×480×0.9
=……………………….

38×36

= 710.53 yds
= (710.53×0.9144) m
=  649.7 m per shift

So, production per shift for single jersey circular knitting machine is 649.7m

Example-02:
Calculate the length in meter of a plain single jersey fabric at 16 courses per centimeter on a 26 inch diameter and 28 gauge machine having 100 feeders. The knitting machine operates for 8 hours at 29 RPM at efficiency of 90%.

Solution:
Given that,
Machine dia= 26 inch,
Machine gauge= 28,
Number of feeder= 100,
Machine speed or cylinder RPM=29 RPM,
Efficiency= 90%= 0.9,
Time= 8 hours= (8×60) =480 minute,
Course per centimeter= 16,
Course per inch (CPI) = 16/0.3937=40.64≈41

So,
Production in meter per shift,
Number of feeder× machine speed× time× efficiency
=…………………………………………………………………..

CPI×36

100×29×480×0.9
=………………………….

41×36

= 848.78 meter per 8 hours,
= (848.78×0.9144) m
= 776.12 m per 8 hours

So, production for this calculation stands at 776.12m per 8 hours.

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