# How to Calculate Lab Dip in Textile Dyeing Factory?

What is Lab Dip or Lab Deep Calculation in Textile Dyeing?

Lab dip or lab deep has great importance in shade matching. Normally it is developed by a dyeing master or chemist in textile wet processing. Lab dip has been done before going to bulk production. The total dyeing production is relay on it. As its importance, this article has presented an easy method for calculating lab dip in the textile dyeing industry. You can follow also the other article on dyeing recipe calculation in the textile wet processing sector.
How to Convert Percentage (%) to gm/l in Textile Dyeing?
The whole conversion can be calculated by using the following formula:

X×10
Y =…………………………………..……….….. (Gm/l)
Liquor ratio (only L value)

Where,
Y indicates the required amount in gm/l.

Example:
Let, the shade percentage of a dyeing shade is 2.5% and liquor ratio (M: L) is 1:10

Now, from the above equation, we get,
2.5×10
Y=…………..…
10
= 2.5gm/l

How to Convert gm/l to Percentage (%) in Textile Wet Processing?
By following the below formula we can solve the above question-

Y× Liquor ratio (only L value)
X =……………………………………….…………… (%)
10

Where,
Y indicates the required amount in gm per liter (gm/l).

Example:
Let, the recipe amount of soda ash is 2.5gm/l and liquor ratio is 1:10

From the above formula we get,
2.5×10
X=…………………….
10
= 2.5%

### Lab Deep or Lab Dip Calculation Method Followed in Textile Wet Processing:

Sample recipe:
Material weight= 5gm,
Soda ash= 10gm/l,
Ant pilling agent= 1gm/l,
Sequestering agent= 2gm/l,
Wetting agent= 0.5gm/l,
Dyes= 1.5%
Glauber salt= 40gm/l,
M: L = 1:10

Stock Solution Concentration:

1. Salt and soda ash= 20%,
2. Dyes= 1%,
3. Wetting agent, sequestering agent, and anti-pilling agent= 1%
Laboratory Dyeing Calculation:

1. Total amount of liquor,
= (5×10) ml
= 50ml
= (50/1000) l
= 0.05l

2. Necessary amount of soda ash,
Recipe amount in gm/l × Amount of liquor (liter)
=…………………………………………………………………………………………
Percentage of Stock solution
10×0.05
=…………………..
20%
= 2.5ml

3. Necessary amount of anti-pilling agent,
Total amount of liquor (liter) × Recipe amount in gm/l
=…………………………………………………………………………
The stock solution in percentage
0.05×1
=…………………
1%
= 5ml

4. Necessary amount of sequestering agent,
Amount of recipe in gm per liter × Total amount of liquor in a liter
=……………………………………………………………………………..………………………………………
Stock solution%
0.05×2
=…………………
1%
= 10ml

5. Necessary amount of wetting agent,
The total amount of liquor in liter × amount of recipe in gm per liter
=……………………………………………………………………………………………………………………
Stock solution percentage
0.05× 0.5
=………………………
1%
=2.5ml

6. Necessary amount of dye solution,
Weight of material× recipe amount in percentage or shade%
=……………………………………………………………………………………………………………..
Stock solution%
5×1.5%
=……………………
1%
= 7.5 ml

7. Necessary amount of Glauber salt,
Total liquor in liter × recipe amount in gm per liter
=……………………………………………………………………………………..……………
The stock solution in percentage
0.05×40
=…………………..
20%
= 10ml

8. Necessary amount of additional water,
= {50ml- (2.5+10+5.0+7.5+10+2.5) ml}
= (50-37.5) ml
= 12.5 ml