**Preparation Method of Stock Solution in Textile:**

Stock solution preparation is a common scenario in the

**textile dyeing**industry. It has importance to complete the dyeing process. The preparation method of this should be known to all who want to make a career in the textile**wet processing**sector. In another article, I have shared two important topics i.e.**dyeing recipe calculation method**and lab dip calculation method. But, in this article, I have presented the preparation process of stock solutions in the**textile industry**.**Stock Solution Preparation Process in Textile:**

In practice, a 1% stock solution is very common in the textile

**dyeing process**. In textile dyeing laboratory work, 1gm solid (powder, 100% concentration) chemicals or dyestuff is taken in a conical flask and pour 100ml of warm (around 45°C) water and stir to dissolve the reagent to make 1% stock solution of that chemicals or**dyes**.To prepare 0.1% stock solution, 10ml or 1ml of 1% solution needs to mix with 90ml or 9ml water respectively.

**In case of liquid reagents,**For example,

Take 10ml acetic acid in a beaker, making it 100ml by pouring necessary amount of water is prepared 10% v/v acetic acid solution.

**Dyeing Calculation in Textile:**

**Percentage amount respect to owg (on the weight of goods):**In the recipe, the percentage amount (on the weight of goods- fiber, yarn, fabric, garment) concerning the material is calculated with the below formula:

**Required amount reagent,**

=Material weight× recipe amount in percentage

**For example,**

The batch weight is 100kg and the shade percentage is 1.5%.

**So,**

The required amount of dyes,

= 100kg× 1.5%

= 1.5kg

**In the case of laboratory dyeing,**The necessary amount of dyes and chemicals are very tiny taking this tiny amount to contain a higher error percent. Accordingly, the required amount of reagents is taken in a diluted form of different concentrations such as 0.1%, 1%, 10%, 20%, etc. In that case, the required amount of reagent is calculated by using the below formula:

Necessary amount of reagent,

Material weight × amount of recipe in percentage

**=……………………………………………………………………………**

The stock solution in percentage

**For example,**5gm sample needs to dye whereas the shade (recipe amount) is 2% and stock solution concentration is 1%.

**So,**By following the above formula we get,

Necessary amount of reagent,

5×2%

=……….…..

1%

= 10ml

**Gm/ amount respect to liquor:**

In the recipe the gm/l amount concerning the liquor is calculated with the following formula:

Required amount reagent,

= Total liquor in liter× recipe amount in gm/l

**For example,**The batch weight is 100kg and leveling agent is 1.5gm/l and M: L is 1:10.

**So,**The required amount of leveling agent,

= {(100×10 liter) × 1.5gm/l}

= 1500 grams

= 1.5 kg

For taking very small amount specially for laboratory purposes the below formula will be-

Necessary amount reagent,

Recipe amount in gm/l × total liquor

**=………………………………………………….**

Stock solution%

**For example,**5gm sample needs to dye where leveling agent (amount of recipe) is 2gm/l, stock solution concentration is 1% and M: L is 1:10 respectively.

**Now,**Following the above formula we get,

Necessary amount reagent,

{2× (50 ml/1000 ml)}

**=………………………..………….**

1%

2× 0.05 l

**=…………………………………..**

1%

**=**10ml