**Warping Calculation Formula:**

In the past, I have presented different article on the mathematical problems and solutions of winding process, important formula for winding calculation in weaving, winding efficiency calculation, mathematical problems and solutions of warping in weaving, which are too much important to know for a textile engineer. As its importance, this article has presented some important formula of warping calculation which will help you to calculate all the mathematical problems of warping in textile weaving industry.

Warping calculation in textile weaving |

**Important Formula of Warping Calculation in Weaving:**

**1. Length of warp,**

= Weight in pounds/ Number of ends,

**Or,**

Weight of warp in pound × count × 840

=……………………………………………………….. (Yds)

Number of ends

**Or,**

Weight of warp in pound × count

=…………………………………………………….. (Hank)

Number of ends

**2. Total length of yarn in the warp,**

Length of warp × No. of ends

=………………………………………………

840

**3. Weight of warp in pounds,**

Length of warp in yds × no. of ends

=……………………………………………………

840× count

**Or,**

Length of warp in yards × number of ends

=…………………………………………………………

**Count of yarn**

**4. Number of ends in the warp,**

Count × weight in pounds × 840

=………………………………………………

Length of warp in yds

**Or,**

Count × weight in pounds

= …………………………………………

Length of warp in hanks

**5. Count of warp or beam count,**

Length of warp in yds × number of ends

=……………………………………………………

840× weight in pounds

**Or,**

Total length of yarn on the beam in yds

=……………………………………………………

840× weight in lbs

**6. Time required in hour,**

Total length of warp to be produced in yds

=………………………………………………………………………..

Actual production in yds per hour × number of machines

**7. Total length of warp to be produced in yds,**

= Length of warp in yds required per beam × No. of beams per set × no. of sets

**Examples of Warping Calculation in Weaving:**

**Example-01:**

Calculate the total number of ends on back beam which weighs 242 pounds. The weight of empty beam as indicated from the marking on its flanges is 62 pounds. The count of the yarn is 40s

**cotton**and the length of warp on the beam is 14000 yds.**Solution:**

Here,

Yarn count= 40s,

Length of yarn in yds= 14000,

Weight of yarn in pounds= (242-62) =180 pounds,

No. of ends in warp=?

So,

Number of ends in the warp,

Count × weight in pounds × 840

=…………………………………………

Length of warp in yds

40×180×840

=………………………

14000

=432

So, number of ends in the warp is 432.

**Example-02:**

Calculate the beam count of the yarn on a set of 6 slasher beams, each of which contains 525 ends of 120000 yds at a weight of warp on back beams is 12000 pounds.

**Solution:**

Here,

Length of warp in yds= 120000,

Weight in pounds= 12000,

Number of ends= (525×6)= 3150,

So,

Beam count,

Length of warp in yds × no. of ends

=…………………………………………………

840× weight in pounds

120000×3150

=………………………….

840×12000

= 37.5s

So, beam count for this

**warping**calculation is 37.5s